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CanadianChris

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Everything posted by CanadianChris

  1. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    Let the fellatio of the military begin...
  2. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    Didn't he last year as well, in that tag title match? Yep,it was the best match on the card as well. Well, THAT's not going to be the same this year.
  3. CanadianChris

    What will Triple H be wearing tonight at the PPV?

    He gave those to O'Haire.
  4. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    Is giving us hilarious feedback really worth 35 bucks? Nah. I'll make it double the hilarious feedback tomorrow night.
  5. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    That's the only thing that motivates me...giving the hilarious feedback.
  6. CanadianChris

    Webcast:

    I'll give you a shiny Canadian nickel.
  7. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    So, should I buy this?
  8. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    Why don't they just use "You Look So Good To Me" instead of that crappy-ass music?
  9. CanadianChris

    The OAO Armageddon PPV Thread- 12/14/03

    Run-in in the Battle of the Sexes match. They may as well put that on the marquee, it's so obvious.
  10. CanadianChris

    One and Only NFL Week 15 Thread

    Listen to that Denver crowd chanting for the champ!
  11. CanadianChris

    One and Only NFL Week 15 Thread

    If Denver loses this game, they don't deserve to go to the playoffs.
  12. CanadianChris

    Please Help

    I think we're suppose to assume that has no effect on the question. And it doesn't. Two objects dropped from the same height will accelerate through the air at the same speed - 10 m/s/s.
  13. CanadianChris

    The Official MLB Offseason Topic

    All that work (with Vlad possibly on the way), and the Orioles are STILL only the fourth-best team in the division.
  14. CanadianChris

    One and Only NFL Week 15 Thread

    Well at least it can't get any worse ...unless they have negative QB ratings That's what I was wondering, as Hasselbeck threw ANOTHER pick.
  15. CanadianChris

    Please Help

    I was surprised they were doing advanced projectiles in a high school physics class, to be honest. Oh well. Good luck CC!
  16. CanadianChris

    One and Only NFL Week 15 Thread

    If Baltimore loses and drops into a tie with Cincinnati, do the Bengals have the tiebreaker? Oh and Hasselbeck's rating has DROPPED in the second half to 0.0.
  17. CanadianChris

    Please Help

    I hear you. I was never really brutal at physics, but I absolutely hated it. That's why I went into statistics in university...nothing even remotely resembling physics there. Oh, and I ran 1200 through those equations, and there's no way that can be the answer if the numbers you gave in the initial problem are correct. Absolutely no way.
  18. CanadianChris

    Please Help

    Found my original mistake...forgot to square time in the second equation. Still doesn't come up with the right answer, though...hmmm.
  19. CanadianChris

    Please Help

    1200????? What the hell?
  20. CanadianChris

    Week 15 results for braves/kkk contests

    Fuck the Redskins. On pace for double digit turnovers, I think. Could be worse, though...my magic number to clinch the division will drop to one now, no matter what happens in the Monday night game.
  21. CanadianChris

    Please Help

    Sure. I may be a little rusty, but here goes... In essence, the question we are trying to answer is, how far will the projectile have fallen once it has travelled 256m? (Because once it has travelled that far, we assume it will meet the object, which is falling perfectly vertically. This is a critical assumption -- without it, we can't solve the problem.) The formula for displacement of an object in one dimension is: d = v(i) * t + 1/2 * a * t^2 where: d = displacement v(i) = initial velocity a = acceleration t = time In two dimensions, though, there are two formulas, one each for the horizontal and vertical components: x = v(ix) * t + 1/2 * a(x) * t^2 y = v(iy) * t + 1/2 * a(y) * t^2 where: x = horizontal displacement y = vertical displacement v(ix) = initial horizontal velocity v(iy) = initial vertical velocity a(x) = horizontal acceleration a(y) = vertical acceleration t = time. OK, now we know these things: v(ix) = 13 m/s (the speed the projectile was fired) v(iy) = 0 m/s (when fired, the object travels perfectly horizontally) a(x) = 0 m/s^2 (assuming air resistance is negligible, there is no acceleration or deceleration of the projectile once it is fired) a(y) = -10 m/s^2 (force of gravity on the projectile) x = 256m (the distance between the projectile and the object) We are trying to find y (how far the projectile -- and thus the object -- have fallen). We do not know t, but we can calculate it from the first formula: x = v(ix) * t + 1/2 * a(x) * t^2 256 = 13 * t + 1/2 * 0 * t^2 256 = 13 * t t = 256/13 = 19.7 s. Now we put that value into the second equation: y = v(iy) * t + 1/2 * a(y) * t^2 y = (0 * 19.7) + (1/2 * -10 * 19.7^2) y = 1/2 * -10 * 388.1 y = -1940.5 m. So, the object falls 1940.5 m before being hit by the projectile.
  22. That's that new Jack Nicholson movie.
  23. CanadianChris

    One and Only NFL Week 15 Thread

    First the phantom timeout against Baltimore, now this. OMG ANTI-SEATTLE NFL CONSPIRACY~!!!
  24. CanadianChris

    One and Only NFL Week 15 Thread

    Only 9 early games, and baring the bills recovering an onside kick down 28-26, Im 9-0. All right, 8-1.
  25. CanadianChris

    Week 15 results for braves/kkk contests

    BWAHAHAHAHAHAHAHA! Ahem. Sorry to hear that. Yeah. And I'm sorry to hear that Chuck changed his Houston pick at the last minute. And I'm SO sorry that your last-second changes aren't doing too well either... Now, now...no need for hostility.
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