

CanadianChris
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The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
Let the fellatio of the military begin... -
The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
Didn't he last year as well, in that tag title match? Yep,it was the best match on the card as well. Well, THAT's not going to be the same this year. -
What will Triple H be wearing tonight at the PPV?
CanadianChris replied to EdwardKnoxII's topic in The WWE Folder
He gave those to O'Haire. -
The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
Is giving us hilarious feedback really worth 35 bucks? Nah. I'll make it double the hilarious feedback tomorrow night. -
The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
That's the only thing that motivates me...giving the hilarious feedback. -
I'll give you a shiny Canadian nickel.
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The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
So, should I buy this? -
The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
Why don't they just use "You Look So Good To Me" instead of that crappy-ass music? -
The OAO Armageddon PPV Thread- 12/14/03
CanadianChris replied to The Mandarin's topic in The WWE Folder
Run-in in the Battle of the Sexes match. They may as well put that on the marquee, it's so obvious. -
Listen to that Denver crowd chanting for the champ!
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If Denver loses this game, they don't deserve to go to the playoffs.
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I think we're suppose to assume that has no effect on the question. And it doesn't. Two objects dropped from the same height will accelerate through the air at the same speed - 10 m/s/s.
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All that work (with Vlad possibly on the way), and the Orioles are STILL only the fourth-best team in the division.
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Well at least it can't get any worse ...unless they have negative QB ratings That's what I was wondering, as Hasselbeck threw ANOTHER pick.
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I was surprised they were doing advanced projectiles in a high school physics class, to be honest. Oh well. Good luck CC!
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If Baltimore loses and drops into a tie with Cincinnati, do the Bengals have the tiebreaker? Oh and Hasselbeck's rating has DROPPED in the second half to 0.0.
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I hear you. I was never really brutal at physics, but I absolutely hated it. That's why I went into statistics in university...nothing even remotely resembling physics there. Oh, and I ran 1200 through those equations, and there's no way that can be the answer if the numbers you gave in the initial problem are correct. Absolutely no way.
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Found my original mistake...forgot to square time in the second equation. Still doesn't come up with the right answer, though...hmmm.
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1200????? What the hell?
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Week 15 results for braves/kkk contests
CanadianChris replied to kkktookmybabyaway's topic in Sports
Fuck the Redskins. On pace for double digit turnovers, I think. Could be worse, though...my magic number to clinch the division will drop to one now, no matter what happens in the Monday night game. -
Sure. I may be a little rusty, but here goes... In essence, the question we are trying to answer is, how far will the projectile have fallen once it has travelled 256m? (Because once it has travelled that far, we assume it will meet the object, which is falling perfectly vertically. This is a critical assumption -- without it, we can't solve the problem.) The formula for displacement of an object in one dimension is: d = v(i) * t + 1/2 * a * t^2 where: d = displacement v(i) = initial velocity a = acceleration t = time In two dimensions, though, there are two formulas, one each for the horizontal and vertical components: x = v(ix) * t + 1/2 * a(x) * t^2 y = v(iy) * t + 1/2 * a(y) * t^2 where: x = horizontal displacement y = vertical displacement v(ix) = initial horizontal velocity v(iy) = initial vertical velocity a(x) = horizontal acceleration a(y) = vertical acceleration t = time. OK, now we know these things: v(ix) = 13 m/s (the speed the projectile was fired) v(iy) = 0 m/s (when fired, the object travels perfectly horizontally) a(x) = 0 m/s^2 (assuming air resistance is negligible, there is no acceleration or deceleration of the projectile once it is fired) a(y) = -10 m/s^2 (force of gravity on the projectile) x = 256m (the distance between the projectile and the object) We are trying to find y (how far the projectile -- and thus the object -- have fallen). We do not know t, but we can calculate it from the first formula: x = v(ix) * t + 1/2 * a(x) * t^2 256 = 13 * t + 1/2 * 0 * t^2 256 = 13 * t t = 256/13 = 19.7 s. Now we put that value into the second equation: y = v(iy) * t + 1/2 * a(y) * t^2 y = (0 * 19.7) + (1/2 * -10 * 19.7^2) y = 1/2 * -10 * 388.1 y = -1940.5 m. So, the object falls 1940.5 m before being hit by the projectile.
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Weekend Box Office Report: 12/12/03 - 12/14/03
CanadianChris replied to a topic in Television & Film
That's that new Jack Nicholson movie. -
First the phantom timeout against Baltimore, now this. OMG ANTI-SEATTLE NFL CONSPIRACY~!!!
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Only 9 early games, and baring the bills recovering an onside kick down 28-26, Im 9-0. All right, 8-1.
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Week 15 results for braves/kkk contests
CanadianChris replied to kkktookmybabyaway's topic in Sports
BWAHAHAHAHAHAHAHA! Ahem. Sorry to hear that. Yeah. And I'm sorry to hear that Chuck changed his Houston pick at the last minute. And I'm SO sorry that your last-second changes aren't doing too well either... Now, now...no need for hostility.